| Voltage Dividers Interview Questions |
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A voltage divider is a resistor with taps to lessen the the ohms. OHM's law states that for resistance (R) divide voltage (E) by amperes (I) or
R= E/I you need to know the amps in the circuit and the desired voltage.
Use an ohm gage to determine where the tap for voltage comes out.
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"suppose that you have a 6v battery and you wish to apply a voltage of only 4V. given an unlimited supply of 1ohm resistors, how could you connect them so as to make a "voltage divider" that produced a 4v output for a 6v input?"
I know that resisters can lower a current, but how can it lower it voltage? Can someone help me with this?
Thank You
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About as good as making lunch. Newer sets have AKB and the computer will offset anything you do. If it is an older set just go to an unused input and adjust the screen voltage as your tubes are probably shot.
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if Vout = (R2 \ R1+ R2) x Vin
How Can It Apply to more than one resistor
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Well, we like to use water a lot in explaining electricity, so try this. Fill a tank with water. Drill a hole at the bottom. The pressure of the full tank is available there, so you get the full flow. Drill a hole half way up. The pressure (voltage) there is only half as much (only half as deep there), so you get half the flow.
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to make sure that only 5 volts actually go into the circuit i am actually using?
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Drop.
The load resistance in parallel with the 2nd resistor of the divider will lower the value of the 2nd resistor, thereby lowering the total sum of the voltage divider.
A lot of people make that mistake when figuring voltage dividers -- they forget there will be a load resistance in parallel with the 2nd voltage divider resistor. However, if the load resistance is greater than 100x the divider resistor, then that effect is negligible.
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Zi = Z1 + Z2ZL/(Z2 + ZL)
where ZL is the input impedance of the load. (Vo being the voltage across Z2 (or ZL))
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if you can provide a schematic diagram much better. given, if the voltage is 12000 and i want the volt ohm meter to read only 12 volts. and i can only use resistors,capacitors and diodes. using voltage divider with a ratio of 1000 to 1.
hey can u help me this? if u can provide a sketch much better. tnx!!
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In a voltage divider configuration ( amplifier ) the output sine wave is inverted or 180 degrees out of phase from the input signal. If the input is an audio signal or sound to the voltage divider configuration, does it changes the output sound because it inverts the sound wave signal?
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be able to speak threw a microphone and hear through an 8ohm speaker: i have R1 10k R2 2.2k, re swamped in first stage, Rc3.9k, second stage same but 1k on Re in second stage 1k on the RL overall gain with third stage has to be 1000
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Hi how are you. Try this.
Vout = Vin.R2 / R2 + R1
(R2 + R1). Vout = Vin. R2
(-R2. Vin + R2) + R1. V out = 0
R2(-Vn +1) + R1.Vout = 0
R2 = (R1.Vout) / (Vin + 1)
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Hello Syddo,
A voltage divider JFET amplifier is one which is biased using two series resistors connected across a source. The junction of the two biasing resistors provides correct bias voltage for the amplifier.
Another method of biasing a JFET is using negative feedback to improve stability which is a form of self biasing. The following link discusses self biasing, and includes information on an experimental setup to realize optimum bias for a JFET RF amplifier.
http://www.qrp.pops.net/jfet-bias-2006.a...
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I'm powering a laser with these specifications:
650nm laser diode, 3.2 VDC
Current consumption is 40mw at 3VDC.
I've got a 4.5 volt wall wart that I was going to power it with. A friend of mine said to create a voltage divider with two resistors. I use this site:
http://ourworld.compuserve.com/homepages...
putting in 4.5 v as my in voltage and 3.2 as my out voltage and 0.25 as my amps but I get really odd values for the resistors (5.2 and 12.8). That doesn't seem right and I don't see resistors for sale out there with those values. What values of resistors should I use?
Thanks
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