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Interview Question :: Doesn;t seem right. Where did I go wrong

A parallel-plate capacitor has dimensions 3.5cm ´ 5.2 cm. The plates are separated by a 1.1-mm thickness of paper (dielectric constant k = 3.7). What is the charge that can be stored on this capacitor, when connected to a 1.5-V battery? (e0 = 8.85 ´ 10-12 C2/N×m2)

HERE IS WHAT I DID......

C = (EoErA)/d

Eo = 8.85x10^-12 F/m

Er = 3.7

A = 18.2x10^-4 m^2

d = 1.1x10^-3 m

so,
C = {(8.85x10^-12)(3.7)(18.2x10^-4)}/(1.1x10... = 54.1781x10^-12 F

so, maximum charge is
Qmax = CVmax = (54.1781x10^-12)(16x10^3) = 866.85x10^-9= 867 nC

867 nC doesn't seem right. Where did I go wrong?

Answers to "Doesn;t seem right. Where did I go wrong"

RE: Doesn;t seem right. Where did I go wrong?
The voltage is 1.5 volts "Qmax = CVmax = (54.1781x10^-12)(16x10^3) = 866.85x10^-9= 867 nC" You have it at 16000 volts!! big difference. .
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RE: Doesn;t seem right. Where did I go wrong?
Looks basically ok but where did your voltage of 16x10^3 come from?? The question says 1.5V not, presumably, the maximum voltage that can be applied before it blows up!
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Interview Question :: Doesn;t seem right. Where did I go wrong

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